\left\langle \psi\left| \mathcal{T}\left\{ \frac{\delta}{\delta\phi}F\lbrack\phi\rbrack \right\} \right|\psi \right\rangle = - \mathrm{i}\left\langle \psi\left| \mathcal{T}\left\{ F\lbrack\phi\rbrack\frac{\delta}{\delta\phi}S\lbrack\phi\rbrack \right\} \right|\psi \right\rangle
